Question 1

Find the interquartile range of the data. 4.6.4.2.9.1.12.7 The interquartile range is

Question 2

$\begin{gathered} \text{First step }organize\text{ the data} \\ 1,\text{ }2,\text{ 4, 4, 6, 7, 9, 12} \\ Second\text{ step calculate median} \\ \operatorname{median}\text{ =}(4+6)/(2)=(10)/(2)\text{ = 5} \\ Median\text{ is 5} \\ \text{Thrid step} \\ -\text{ For the first four numbers, calculate the median} \\ 1,\text{ }2,\text{ 4, 4} \\ \operatorname{median}\text{ 1=}(2+4)/(2)=(6)/(2)=3 \\ \\ -\text{ For the second four numbers, calculate the median} \\ \text{6, 7, 9, 12} \\ \operatorname{median}\text{ 2=}(7+9)/(2)=(16)/(2)=8 \\ \operatorname{median}\text{ 2=}8 \\ \\ \text{Interquartile range =median 2-median 1} \\ \text{Interquartile range =8-3} \\ \text{Interquartile range =}5 \\ \text{the Interquartile range is 5} \end{gathered}$

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