Question

Claim: Most adults would ease all of their personal information online if they could. A software firm survey of 693 randomly selected adults showed that 58% of them would orase all of their personal information onlineif they could. Find the value of the test statisticThe value of the test statistics(Round to two decimal places as needed)

Answer 1

Data:

P: sample proportion

p0: hypothesis proportion

n: sample size

P: 58% = 0.58

p0: >50% (most adults)= 0.5

n:693

To find the value of the test statistic you use the next formula:

`z=\frac{P-p0}{\sqrt[]{(p0(1-p0))/(n)}}`

Then you get:

`z=\frac{0.58-0.5}{\sqrt[]{(0.5(1-0.5))/(693)}}`
`z\approx4.21`Then, the value of the test statistic is approx. 4.21