175k views
1 vote
A certain type of bacteria,given a favorable growthMedium, doubles in population every 6.5 hours. Given that there were approximately 100 bacteria to start with, how many bacteria will there be in a day and a half?

User Salathe
by
8.3k points

1 Answer

3 votes

A certain type of bacteria,

given a favorable growth

Medium, doubles in population every 6.5 hours. Given that there were approximately 100 bacteria to start with, how many bacteria will there be in a day and a half?

we have that

the exponential growth function that represent this situation is


y=100(2)^{((t)/(6.5))}

where

x is the number of hours

y is the total bacteria

so

For a day -------> t=24 hours

substitute


\begin{gathered} y=100(2)^{((24)/(6.5))} \\ y=1,293\text{ bacteria} \end{gathered}

For a half day -------> t=12 hours

substitute


\begin{gathered} y=100(2)^{((12)/(6.5))} \\ y=360\text{ bacteria} \end{gathered}

For a day and a half -------> t=36 hours

substitute


\begin{gathered} y=100(2)^{((36)/(6.5))} \\ y=4,648\text{ bacteria} \end{gathered}

User Mysuperass
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories