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Which of the following would you use to find the number of different combinations of six-person nominating committees that could be chosen from a class of 25 students?

Which of the following would you use to find the number of different combinations-example-1

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To answer this question, we need to remember that in a committee is not important the order of the members. In this case, we can use combinations.

Combinations of k elements from n can be represented by the next formula:


nC_k=(n!)/((n-k)!k!)

Therefore, if we have that k = 6, and n = 25. Then, we have:


25C_6=(25!)/((25-6)!6!)

And since:


25C_6=(25!)/((25-6)!6!)=(25!)/(6!(25-6)!)

In summary, therefore, the correct option is C.

User SagiLow
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