![364\: miles](https://img.qammunity.org/2023/formulas/mathematics/college/5dbliyogno2a4jow9p1uqm2v74jf1jmblm.png)
1) The best way to tackle this question is to think of rational equations. Since, time, rate and distance are related.
2) So, we can start writing the following:
![\begin{gathered} t=(d)/(r)\Rightarrow rt=d\Rightarrow t=(d)/(r) \\ Country\: roads=(3d)/(65) \\ Through\: Towns=(d)/(35) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/758nqjlkjx3n9zymrqrk7yvb304ache7ud.png)
So, let's solve it by equating the sum of these expressions to the spent time: 4 hours (common to both)
Now we have the LCM
![\begin{gathered} (d)/(35)+(3d)/(65)=4 \\ (13d+7d)/(455)=(1820)/(455)*455 \\ 13d+7d=1820 \\ 20d=1820 \\ (20d)/(20)=(1820)/(20) \\ d=91 \\ 3d=273 \\ 273+91=364 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8nrbp0w6l1qq6b354hzm0kzonpfo9zma69.png)
Note that adding them up, the distance in country roads and the distance in towns.