Question

write the equation of the line in slope intercept form, and graph using the slope and the y intercept x+4y=8

Answer 1

The general equation of a line in slope-intercept form is given below as

`y=mx+c`

The equation of the line given is

`x+4y=8`

Concept:

We will make y the subject of the formula

`\begin{gathered} x+4y=8 \\ 4y+x-x=8-x \\ substract\text{ x from both sides} \\ 4y+x-x=8-x \\ 4y=8-x \\ divide\text{ bpoth sides by 4} \\ (4y)/(4)=-(x)/(4)+8 \\ y=-(1)/(4)x+2 \end{gathered}`

Hence,

The equation of the line in slope-intercept form is

`\Rightarrow y=-(1)/(4)x+2`