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Find the equation of the parabola by short cut method A) Focus (5,1) and Vertex (2,1)B) Focus (0,2) and Directrix: y=6

User Bradvido
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Solution:

(A) Given Focus (5,1) and Vertex (2,1)

We are required to find the equation of the parabola

Substituting the values of h, k and f, we have


\begin{gathered} x=(1)/(4(5-2))(y-1)^2+2 \\ \\ x=(1)/(4(3))(y-1)^2+2 \\ \\ x=(1)/(12)(y-1)^2+2 \\ \\ x=((y-1)^2)/(12)+2-------Vertex\text{ form} \end{gathered}

Or in standard form, we have


x=(y^2)/(12)-(y)/(6)+(25)/(12)



Find the equation of the parabola by short cut method A) Focus (5,1) and Vertex (2,1)B-example-1
User Vozaldi
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7.6k points

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