Question

I answered correctly for this math question but I'm not sure why could you explain?

Answer 1

`207yd^2`

Step-by-step explanation:

Given that:

Side length of the base of the pyramid, b = 12 yd

Slant height, s = 11.5 yd

Height, h = 10.4 yd

Find the lateral surface area using the formula

`LA=(1)/(2)Ps`

where P is the perimeter of the base.

First, find P.

`\begin{gathered} P=12+12+12 \\ =36 \end{gathered}`

Substitute the values into the formula to find the lateral surface area.

`\begin{gathered} LA=(1)/(2)\cdot36\cdot(11.5) \\ =207yd^2 \end{gathered}`

The lateral surface area of the equilateral triangular pyramid is 207 square yards.