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Find the slope of the line that is perpendicular to the graph of the point (-3,-1) and (0,-4)

User Izb
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In this question, we have to find the slope of the perpendicular line to the graph of the point (-3,-1) and (0,-4).

For that, first, find the slope of the given line.

The slope (m) is calculated by the difference of y values over the x.

m = (y2 - y1)/ (x2 - x1)

Here, the points are:

(-3 , -1)

x1 = -3

y1 = -1

similarly, in (0, -4)

x2 = 0

y2 = -4

Now, put these values in the given equation.

m = (-4 - (-1)) / (0 - (-3))

m = (-4 + 1) / (0+3)

m = -3/ 3

m = -1

Now, the perpendicular slopes are negative reciprocals of each other.

For example, for a given line of slope 'x', the slope of the perpendicular line would be -1/x.

The negative reciprocal of -1 is -1/(-1) = 1.

Hence, the slope of the perpendicular line to the graph of the point (-3,-1) and (0,-4) would be 1.

User AVB
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