94.0k views
3 votes
Find the slope of the line that is perpendicular to the graph of the point (-3,-1) and (0,-4)

User Izb
by
8.5k points

1 Answer

5 votes

In this question, we have to find the slope of the perpendicular line to the graph of the point (-3,-1) and (0,-4).

For that, first, find the slope of the given line.

The slope (m) is calculated by the difference of y values over the x.

m = (y2 - y1)/ (x2 - x1)

Here, the points are:

(-3 , -1)

x1 = -3

y1 = -1

similarly, in (0, -4)

x2 = 0

y2 = -4

Now, put these values in the given equation.

m = (-4 - (-1)) / (0 - (-3))

m = (-4 + 1) / (0+3)

m = -3/ 3

m = -1

Now, the perpendicular slopes are negative reciprocals of each other.

For example, for a given line of slope 'x', the slope of the perpendicular line would be -1/x.

The negative reciprocal of -1 is -1/(-1) = 1.

Hence, the slope of the perpendicular line to the graph of the point (-3,-1) and (0,-4) would be 1.

User AVB
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories