Answer:
[H3O (+)] = 7.1 x 10⁻¹⁰ M.
Step-by-step explanation:
To solve this problem, we have to use the following equation:
![\lbrack H_3O^+]\lbrack OH^-]=1\cdot10^(-14).](https://img.qammunity.org/2023/formulas/chemistry/college/h2tbdp82uuvv6am1smb2o1g6g6r4uhaobi.png)
As we have the value of [OH (-)], we just have to solve for [H3O (+)] and replace the data that we have, like this:
![\begin{gathered} \lbrack H_3O^+]=(1\cdot10^(-14))/(\lbrack OH^-])=(1\cdot10^(-14))/(1.4\cdot10^(-5)), \\ \lbrack H_3O^+]=7.1\cdot10^(-10)\text{ M.} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/n6b3egmgb9bsewjgj006ryjjruuklqp2ou.png)
The answer would be that the concentration of [H3O (+)] = 7.1 x 10⁻¹⁰ M.