Question

Graph the equation y= 3/2-3 bu plotting points

Answer 1

I will assume the linear equation is

`y=(3)/(2)x-3`

We can take 3 points for x and find corresponding y values for them. Then we plot these 3 coordinates and draw a line through them.

• When ,x = 0,,

`\begin{gathered} y=(3)/(2)(0)-3 \\ y=-3 \end{gathered}`

• When ,x = 2,,

`\begin{gathered} y=(3)/(2)(2)-3 \\ y=0 \end{gathered}`

• When ,x = 4,,

`\begin{gathered} y=(3)/(2)(4)-3 \\ y=3 \end{gathered}`

Thus, the 3 coordinates are:

`\begin{gathered} (0,-3) \\ (2,0) \\ (4,3) \end{gathered}`

The graph of the line >>>>>>