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Which of the following sets of ordered pairs do not belong

Which of the following sets of ordered pairs do not belong-example-1
User Done
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Answer:

First and last options do not belong to a one-to-one function

Explanation:

Definition of a one-to-one function

A function f is 1 -to- 1 if no two elements in the domain of f correspond to the same element in the range of f .

In other words, for each x value there is only one y value

And, no y value corresponds to more than one x

In the given problem we test the set of ordered pairs to see if a y-value corresponds to more than one x-value. If so, the ordered pair does not belong to a one-to-one function

  1. In the first option we see that the value of x = 1 maps to two y values : -4 and -2. By the definition of a function, a single x value cannot result in two different y values. So this set does not even belong to a function let alone a 1:1 function
  2. The second option - set belongs to a 1:1 function since for any value of x there is only one value of y
  3. The third option is a 1:1 function
  4. The last option does have unique y values for x values so it is a function but for x = 2 and x = 5 we get the same y= -1 so it is not a 1:1 function

User Juan Vega
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