Question

Rectangle ABCD is shown on the grid.What is the area of rectangle ABCD in square units?O 3v17 square units06/17 square unitsFEE& (33)17 square unitsO 34 square units123 4 5 62--Cla 5)Mark this and retumSave and ExitNextSubmit

Answer 1

Given the figure, we are asked to find the are of the rectangle. To do this, the first thing we need to do is to find the length and width of the rectangle.

To find the length of the rectangle, let us use the points (1,-5) and (3,3).

Use the distance formula to find the length

`L=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`
`L=\sqrt[]{(3-1_{})^2+(3-(-5))^2}`
`L=\sqrt[]{(2)^2+(8)^2}`

`L=\sqrt[]{4+64}`
`L=\sqrt[]{68}`

Next, to find the width, we will use the points (-1,4) and (3,3)

Use the distance formula

`W=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`
`W=\sqrt[]{(3-(-1))^2+(3-4)^2}`
`W=\sqrt[]{(4)^2+(-1)^2}`
`W=\sqrt[]{16+1}`
`W=\sqrt[]{17}`

Now, to find the area, we just need to multiply the length by the width.

`A=LW`
`A=\sqrt[]{68}\cdot\sqrt[]{17}`
`A=\sqrt[]{1156}`
`A=34`

Therefore, the answer is 34 square units.