1 Answer

Ines · Answer 1 · 2023-06-16T03:58:06+0000

Answer

$\operatorname{\lim}_(x\to\pi^(-))f(x)=\infty$

Vertical asymptote: x = π.

$\lim_(x\to(2\pi)^-)f(x)=-\infty$

Vertical asymptote: x = 2π.

Step-by-step explanation

Given the graph of the function

we can find the limit of the function when x approaches π from the left:

Thus:

$\lim_(x\to\pi^-)f(x)=\infty$

indicating that it has a vertical asymptote at x = π.

Then, we can also find the limit of the function when x approaches 2π from the left:

$\operatorname{\lim}_(x\to(2\pi)^(-))f(x)=-\infty$

indicating that it has a vertical asymptote at x = 2π.

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