Given the equation:
f(x) = -2x² + 3x + 1
We are asked to find the zeros of the quadratic function.
Using the quadratic formula:
x = -b ± √b² - 4 ac
2a
Where:
a = -2
b = 3
c = 1
Lets input into the formula:
x = -(-3) ± √(3)² - 4 (-2 * 1)
2 * -2
x = 3 ± √9 - 4 (-2)
-4
= 3 ± √9 - 4 (-2)
-4
= 3 ± √9 - 4 (-2)
-4
= 3 ± √9 - 4 (-2)
4
= 3 ± √9 + 8
4
= 3 ± √17
4
x = 1.8, -0.3
Therefore, the correct answer is (-0.3, 0) and (1.8, 0)