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A die is thrown. What is the probability of getting a number 1 or even number?1/22/33/41

User Zvavybir
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1 Answer

3 votes

Given:

Two dies are thrown.

Required:

What is the probability of getting a number 1 or even number?

Step-by-step explanation:

The probability


=\frac{\text{ Number of favorable cases}}{\text{ Total number of cases}}
\begin{gathered} \text{ The favorable outcomes are the number 1 and the even numbers} \\ 2,4\text{ and }6,\text{ That's four outcomes. So,} \\ P(\text{ getting an even number or a 3})=(4)/(6)=(2)/(3). \end{gathered}

Answer:


\text{ The probability is }(2)/(3).

User Sergii Volchkov
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