Given:
In the first option, Charlie can pay $39 for unlimited rides,
In the second option, Charlie can pay $15 for admission plus $1 per ride.
Required:
We need to find the number of rides that the two options wind up costing him the same amount.
Step-by-step explanation:
Let C be the cost of the ride.
Let r be the number of the ride.
Consider the first option.
![C=39](https://img.qammunity.org/2023/formulas/mathematics/college/eiulvgfd1l46s3bbcat31gxurv74xwq06r.png)
Consider the second option.
![C=15+r(1)](https://img.qammunity.org/2023/formulas/mathematics/college/5esaip1ajdncebgvw0x7x3agqqm64959c1.png)
Substitute C=39 in this equaiton.
![39=15+r(1)](https://img.qammunity.org/2023/formulas/mathematics/college/u1czpta80i5n2nbyo2qnvlzemwyj23pj4l.png)
Substract 15 from both sides of the equation.
![39-15=15+r(1)-15](https://img.qammunity.org/2023/formulas/mathematics/college/ajwbeoboh7y3tiepxjci98gqhgikv3buqb.png)
![24=r](https://img.qammunity.org/2023/formulas/mathematics/college/zhtaoa418mf82mab3wjkxhbf02vn3f93wl.png)
![r=24\text{ rides.}](https://img.qammunity.org/2023/formulas/mathematics/college/b2k6aho1pa05oaz4yf5du71v59nri7yina.png)
The number of rides that the two options wind up costing him the same amount is 24 rides.
The cost of the ride is C =39.
Final answer:
The number of rides =24.
The cost of the rides =39.