Question

How many grams of NaOH are present in a 1.3 mole sample?

Answer 1

52 grams

Explanations:

Given the following parameters from the question:

Moles of NaOH = 1.3 moles

The formula for calculating the mass of a compound is expressed as;'

`Mass\text{ of NaOH}=mole* molar\text{ mass}`

Determine the molar mass of NaOH

`\begin{gathered} molar\text{ mass }of\text{ NaOH}=23+16+1 \\ molar\text{ mass of NaOH}=40g\text{/mol} \end{gathered}`

Determine the mass of NaOH

`\begin{gathered} Mass=moles* molar\text{ mass} \\ Mass=1.3moles*40(g)/(mol) \\ Mass=52grams \end{gathered}`

Hence the mass of NaOH present in a 1.3moles of the sample is 52 grams