Question

In triangle IJK, J = 800cm, k = 240 cm and angle I=173 degrees. Find the area of triangle IJK, to the nearest square centimeter.

Answer 1

11,700cm²

Explanation:

Area of the triangle = 1/2*JK sin<I

Given

J = 800cm

K = 240cm

<I = 173 degrees

Substitute

Area of the triangle = 1/2 * 800 * 240 sin 173

Area of the triangle = 400 * 240sin 173

Area of the triangle = 400 * 29.25

Area of the triangle = 11,699.5

Area of the triangle to the nearest square centimeter is 11,700cm²