Answer:
![80\text{ L}](https://img.qammunity.org/2023/formulas/chemistry/college/tnb17zt8xjud1n78yvb4dcqbpttfg2j8j9.png)
Step-by-step explanation:
Here, we want to get the volume of the gas at a reduced pressure
From Boyle's law, we have it the volume and pressure of a given mass of gas are inversely proportional
Mathematically:
![\begin{gathered} P_1V_1\text{ = P}_2V_2 \\ \\ V_2\text{ = }(P_1V_1)/(P_2) \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/mxt3kyttawekzo9e5gg79cp0qxahuifl96.png)
Where:
P1 is the initial pressure wich is 3800 mmHg
V1 is the initial volume which is 12 L
P2 is the final pressure which is 570 mmHg
V2 is the final volume which is ?
Substituting the values, we have it that:
![\begin{gathered} P_2\text{ = }(3800*12)/(570) \\ \\ P_2\text{ = 80 L} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/st7eiugys2vlffli685be592wlw0ivmbvi.png)