Question

Find the first four terms of the sequence given by the following.=an−386−n1

Answer 1

Step-by-step explanation:

We are given the formula for a sequence as shown below;

`a_n=38-6(n-1)`

Note that n represents the nth term.

Therefore, to calculate the first term for example, we shall replace n with 1, for the second term, we shall replace n with 2 and so on.

Therefore, to calculate the first 4 terms of the sequence, we shall take the following steps;

`\begin{gathered} 1st\text{ }term: \\ a_1=38-6(1-1) \\ a_1=38-6(0) \\ a_1=38 \end{gathered}`
`\begin{gathered} 2nd\text{ }term: \\ a_2=38-6(2-1) \\ a_2=38-6(1) \\ a_2=38-6 \\ a_2=32 \end{gathered}`
`\begin{gathered} 3rd\text{ }term: \\ a_3=38-6(3-1) \\ a_3=38-6(2) \\ a_3=38-12 \\ a_3=26 \end{gathered}`
`\begin{gathered} 4th\text{ }term: \\ a_4=38-6(4-1) \\ a_4=38-6(3) \\ a_4=38-18 \\ a_4=20 \end{gathered}`

Therefore, the first 4 terms are;

ANSWER:

`38,32,26,20`