Step-by-step explanation:
We are given: Pressure of Xe gas = 0.607 atm
: Temperature of Xe gas = 24 degrees Celsius
: Volume of Xe gas = 22.1 L
Temperature Xe gas in Kelvins = 24.0 + 273 = 297 K
We know: Ideal gas constant = 0.082 L.atm/K.mol
To find the number of moles of Xe gas, we use the ideal gas law:
![\begin{gathered} PV\text{ = nRT} \\ \\ \therefore n\text{ = }(PV)/(RT) \\ \\ \text{ = }(0.607*22.1)/(0.082*297) \\ \\ \text{ = 0.55 mol} \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/fjc84wt3y4ouy7vby493d3xr5sb8wj44vs.png)
Answer:
The number of moles of Xe gas present is 0.55 mol.