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In the following combustion reaction you use 15.0 grams of C3H8. How many moles of H2O was produced?C3H8 + 5O2 → 3CO2 + 4H2O

User MJ Studio
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In order to answer this question we will need first to set up the properly balanced equation, which the question already gave us:

C3H8 + 5 O2 -> 3 CO2 + 4 H2O

Now the molar ratio between C3H8 and H2O is 1:4, which means that for every 1 mol of C3H8, we will end up with 4 moles of H2O, now we have to find out the number of moles present in 15.0 grams of C3H8, we will do that by using its molar mass, 44.1 g/mol

44.1 g = 1 mol

15.0 g = x moles

x = 0.34 moles of C3H8

Now we have the number of moles of C3H8, and we can find the number of moles of H2O by using the molar ratio

1 C3H8 = 4 H2O

0.34 C3H8 = x H2O

x = 1.36 moles of H2O are produced

User Billda
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