Answer:
Explanation:
Let Musa's mark = m
Adenike obtained 19 marks more than Musa, therefore:
Adenike's mark, a = m+19
If Adenike had obtained one and a half times her own mark, she would have scored 6 marks more than twice Musa's mark.
![\begin{gathered} \text{ One and half times Adenike's mark}=1(1)/(2)a \\ 6\text{ more than twice Musa's mark}=2m+6 \\ \implies1(1)/(2)a=2m+6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ycp3rhhcfq2ace84mffxku8c2e3b2haz17.png)
Substitute a=m+19 and solve for m: