Answer:
281 K
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 1180 mL
Initial temperature (T₁) = 417 K
Final volume (V₂) = 0.796 L
Final temperature (T₂) =?
Next, we shall convert 0.796 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.796 L = 0.796 L × 1000 mL / 1 L
0.796 L = 796 mL
Finally, we shall determine the final temperature as follow:
Initial volume (V₁) = 1180 mL
Initial temperature (T₁) = 417 K
Final volume (V₂) = 796 mL
Final temperature (T₂) =?
V₁/T₁ = V₂/T₂
1180 / 417 = 796/T₂
Cross multiply
1180 × T₂ = 417 × 796
1180 × T₂ = 331932
Divide both side by 1180
T₂ = 331932 / 1180
T₂ = 281 K
Therefore, the final temperature of the of the gas is 281 K