We will have the following:
7x - 32 & 5x -27 & 180 -(9x -8)
The last onse since we are given the exterior angle that is supplementary from the angle we need, we then proceed as follows:

That since the sum of all internal angles of a triangle equals 180°, we now solve for x:

Now that we have x, we then replace in the functions, and we will get:




