Question

A gas at 300 kPa, is in a sealed container of volume 100 cm3 at 30°C. If the container is heated to 100°C, what is pressure of the gas inside the container?

Answer 1

Given:

Pressure, P = 300 kPa

Volume, V = 100 cm³

Temperature, T = 30°C

Let's fin the pressure of the gas inside the container if it is heated to 100°C.

Apply the Gay-Lussac's law:

`(P_1)/(T_1)=(P_2)/(T_2)`

Where:

P1 = 300 kPa

T1 = 30 + 273 = 303 K

T2 = 100 + 273 = 373 K

V1 = V2 (since the container is sealed).

Let's solve for P2.

Rewrite the formula for P2:

`\begin{gathered} P_2=(P_1T_2)/(T_1) \\ \\ P_2=(300*373)/(303) \\ \\ P_2=(111900)/(303) \\ \\ P_2=369.31\text{ kPa} \end{gathered}`

Therefore, the pressure if the container is heated to 100°C is 369.31 kPa.

ANSWER:

369.31 kPa