Answer
The probability of drawing a red card or a face card is 8/13
Step-by-step explanation
Let A be the event of red card, n(A) = 26
Let B represent the event of face card, n(B) = 12
The total possible outcome, n(S) = 52
From mutually exclusive event, (Addition law of probability), we have
p(A∪B) = p(A) + n(B) - p(A∩B)
p(A) = n(A)/n(S) = 26/52
p(B) = n(B)/n(S) = 12/52
But p(A∩B) = 3 + 3 = 6/52 that is (3 clover face cards + 3 spade face cards)
Therefore, the probability of drawing a red card or a face card is
![\begin{gathered} p\mleft(A\cup B\mright)=(26)/(52)+(12)/(52)-(6)/(52) \\ p(A\cup B)=(32)/(52) \\ p(A\cup B)=(8)/(13) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/d5hn1svc0lryjucsv9vjmg500r4vp3nv5z.png)