How do you evaluate for x = 3 and y = 6?

asked Nov 14, 2023 98.7k views

4 votes

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3 votes

Solution

Given

$\begin{gathered} (x^3y^5)/(x^5y^2) \\ \\ x=3\text{ and }y=6 \\ (3^3*6^5)/(3^5*6^2)=(3^3*2^5*3^5)/(3^5*2^2*3^2) \end{gathered}$

$\begin{gathered} =(2^5*3^(3+5))/(2^2*3^(5+2)) \\ \\ =(2^5*3^8)/(2^2*3^7) \\ \\ =2^(5-2)*3^(8-7) \\ \\ =2^3*3=24 \end{gathered}$

Correct option D

Qualaelay answered Nov 18, 2023

2.7k points

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