![\begin{gathered} y=4.5x+7.5 \\ y=-3.5x-4.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/pipcx5tlq7yauvh66qdbx4923fyqh9dp2z.png)
To solve the system of equations using substitution we replace the value of y from the first equation into the second equation to find the value of x.
![4.5x+7.5=-3.5x-4.5](https://img.qammunity.org/2023/formulas/mathematics/high-school/99lvt7fn06sxc1a8n3r189ay20wtwk8zze.png)
solve the equation for x
![\begin{gathered} 4.5x+3.5x=-4.5-7.5 \\ 8x=-12 \\ x=-(12)/(8) \\ x=-1.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/hecciev6uxhyiiix91yvj8momga0pe1t6y.png)
using the value of x in either equation find the value of y
![\begin{gathered} y=4.5(-1.5)+7.5 \\ y=-6.75+7.5 \\ y=0.75 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/c3oguzipxn6re05d2969sw6x3l02is5gjf.png)
The solution for the system of equations is:
X= -1,5
y= 0.75