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29 votes
29 votes
A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?

User Albaregar
by
2.8k points

1 Answer

15 votes
15 votes

Answer:

v=30 m/s

Step-by-step explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity


h = (1)/(2) * g * t {}^(2)

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s

User Rudi Angela
by
2.6k points