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What is the vertex of the parabola represented by y = - x^2 + 6x - 5-x has a variable of 2

User Xdemocle
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1 Answer

3 votes

Answer:

The vertex of the parabola is (3, 4)

Step-by-step explanation:

Given the equation:


y=-x^2+6x-5

This is in the form:


y=ax^2+bx+c

With a = -1, b = 6, and c = -5

The x-coordinate of the vertex is given as:


\begin{gathered} x=-(b)/(2a) \\ \\ =-(6)/(2(-1)) \\ \\ =(6)/(2) \\ \\ =3 \end{gathered}

Substituting x by 3 in the equation of the parabola, we can obtain the y-coordinate of the vertex.

Doing that, we have:


\begin{gathered} y=-(3^2)+6(3)-5 \\ =-9+18-5 \\ =4 \end{gathered}

Therefore, the vertex of the parabola is (3, 4)

User Mdma
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