Question

A current of 9.50 A flows in a conductor for 1.50 s. How many electrons pass a given point in the conductor during this time? answer:______electrons

Answer 1

8.9 x 10^(19) electrons

Step-by-step explanation:

First, we need to calculate the charge that passes through the conductor. It can be calculated as:

`\begin{gathered} I=(Q)/(t) \\ \\ Q=I\cdot t \end{gathered}`

Replacing I = 9.50 A and t = 1.50 s, we get:

`\begin{gathered} Q=(9.50\text{ A\rparen\lparen1.50 s\rparen} \\ Q=14.25\text{ C} \end{gathered}`

Then, the charge of 1 electron is 1.6 x 10^(-19) C, so we can calculate the number of electrons as

`\frac{14.25\text{ C}}{1.6*10^(-19)C\text{ /electron}}=8.9*10^(19)\text{ electrons}`

Therefore, the number of electrons is 8.9 x 10^19