Answer:
i.
Graphing the proportional relationship;
![y=1300x](https://img.qammunity.org/2023/formulas/mathematics/college/3acbspa4ffq3p8m3tynxdf9hpysgixyuzy.png)
Note that the y-axis represents the amount of water in gal and the x-axis represents the time in hours.
ii.
The second city pool fills at a faster rate than the first city pool.
![\begin{gathered} r=1300\text{ gallons/hour} \\ r_2=3600\text{ gallons/hour} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3yv3av1z56thy1i1va0pbguxnbelx8uu3u.png)
Step-by-step explanation:
i.
Given that the first pool is refilled at 5,200 gallons of water in 4 hours.
The rate of refilling the first pool is;
![\begin{gathered} r=(5200)/(4)\text{ gallons/hour} \\ r=1300\text{ gallons/hour} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qqc6vxxu2tn771ombsf8elvlkh5gqkadil.png)
Graphing the proportional relationship;
![y=1300x](https://img.qammunity.org/2023/formulas/mathematics/college/3acbspa4ffq3p8m3tynxdf9hpysgixyuzy.png)
Note that the y-axis represents the amount of water in gal and the x-axis represents the time in hours.
ii
The second city pool as shown on the graph fills 10,800 gallons in 3 hours.
The rate of refilling the second city pool is;
![\begin{gathered} r_2=(10800)/(3)\text{ gallons/hour} \\ r_2=3600\text{ gallons/hour} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/40hanbjpjp3wqanqptsetdy9wozrzzth6r.png)
From the rate of refilling for the second city pool and the first city pool;
![\begin{gathered} r=1300\text{ gallons/hour} \\ r_2=3600\text{ gallons/hour} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3yv3av1z56thy1i1va0pbguxnbelx8uu3u.png)
We can observe that the rate of refilling for the second city pool is higher than that of the first city pool.
Therefore, the second city pool fills at a faster rate than the first city pool.