Boat original speed: 18 knots
Boat original direction: 234°
Current speed: 8 knots
Current direction: 124° + 180° = 304° (because it says "flowing from a bearing of 124°")
The diagram of the problem is as follows:
We can calculate the velocity of the boat and the current using the speed and the direction:
![\begin{gathered} \vec{v}_(boat)=(18\cos234\degree,18\sin234\degree)=(-10.5801,-14.5623) \\ \\ \vec{v}_(current)=(8\cos304\degree,8\sin304\degree)=(4.47354,-6.6323) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/f303l7gptbap57pk1hdy3aa7hgqezsb9rw.png)
Finally, the resultant velocity for the boat is the vector sum between the original velocity of the boat and the velocity of the current:
![\begin{gathered} \vec{v}_(resultant)=\vec{v}_(boat)+\vec{v}_(current)=(-10.5801,-14.5623)+(4.47354,-6.6323) \\ \\ \therefore\vec{v}_(resultant)=(-6.107,-21.195)\text{ knots} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1smvz91qrpty3tiba45mll24vv7y6jvw0m.png)
And the resultant speed is 22.057 knots