Question

The graph of g(x)=secx has vertical asymptotes whereversinx is undefinedsecx=0secx=∞cosx=0

Answer 1

Answer:

The correct option is D

The function has vertical asymptotes wherever

cos x = 0

Step-by-step explanation:

Given that

`g(x)=\sec x`

Note that

`\sec x=(1)/(\cos x)`

This has vertical asymptotes wherever the denominator is zero, that is;

`\cos x=0`