To determine the equation of the line you have to use the point-slope form

Where
(x₁, y₁) are the coordinates of one point on the line
m is the slope
We know two points crossed by the line (0, 4) and (-9,-3), using them we can calulate the slope as:

Where
(x₁, y₁) are the coordinates of one point on the line
(x₂, y₂) are the coordinates of a second point on the line

Now that we know the slope of the line, we can determine the equation using
m=7/9 and (0,4)

Pass "-4" to the other side of the equation to express the equation in slope-intercept form
