You have the following proportion given in the exercise:
![(P)/(100)=(A)/(B)](https://img.qammunity.org/2023/formulas/mathematics/college/uf9nx2eb2g9hnty5z0tcg78m5mng5oab6n.png)
Where "P" is the percent, "A" is the amount and "B" is the base.
In this case, you need to find the 25% of 50. Then, you can set up that:
![\begin{gathered} P=25 \\ B=50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qw07ge6lu0ymk72s6mxbispgywzk6x8m2s.png)
Then, "A" is the value you need to find.
Hence, substituting values into the proportion and solving for "A", you get:
![\begin{gathered} (25)/(100)=(A)/(50) \\ \\ (25)/(100)\cdot50=A \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9qx4uvulwhil8e3zwx9pehat0y8nofc4nn.png)
![\begin{gathered} (1250)/(100)=A \\ \\ A=12.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fwfgjv6jndcom9edzr2znk10gvtaijiq74.png)
Therefore, the answer is:
![12.5](https://img.qammunity.org/2023/formulas/physics/high-school/st4oec54zofvicjl47rs9xj9mg3gqyyr30.png)