Question

The shortest leg of a right triangle is 27 units. The other leg is the solution to 2x-5=67. What is the length of the hypotenuse??

Answer 1

start by solving the other leg

`\begin{gathered} 2x-5=67 \\ 2x=67+5 \\ 2x=72 \\ x=36 \end{gathered}`

draw the triangle

Use the pythagorean theorem to find the hypotenuse

`\begin{gathered} c^2=a^2+b^2 \\ c=\sqrt[]{a^2+b^2} \\ c=\sqrt[]{(27)^2+(36)^2} \\ c=\sqrt[]{2025} \\ c=45 \end{gathered}`