Question

(gh)^0 I'm very confused can you show me how to solve this

Answer 1

The expression is:

`(9d^(10))^(-2)`

Simplify the expression:

1. Multiply the exponent outside the parenthesis with every exponent inside the parenthesis,

`\begin{gathered} (9d^(10))^(-2)=9^2d^((-10)*2) \\ (9d^(10))^(-2)=9^(-2)d^(-20) \end{gathered}`

Since, exponents in negative form are express as fraction with 1 as numerator.

`\begin{gathered} \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=9^(-2)d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=(1)/(9^2)* d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=(1)/(81)^{}d^{\mleft\{-20\mright\}} \end{gathered}`

Answer: 1/81d^(-20)