Question

Because atoms are extremely small and spread far apart, at standard temperature and pressure (25°C and 1 atm) one mole of any gas occupies a volume of ______.

Answer 1

24.436L

Explanations:

According to the ideal gas equation:

`PV=nRT`

where:

P is the pressure = 1atm

V is the volume

n is the number of moles

R is the gas constant

T is the temperature (in kelvin)

Given the following parameters

P = 1 atm

T = 25° or 298 K

n = 1 mole

R = 0.082 atmLmol-1K-1

Required parameter

The volume of the gas V

Substitute the given parameters into the formula to get the volume

`\begin{gathered} V=(nRT)/(P) \\ V=(1mole*0.082atmL*298K)/(1atm* molK) \\ V=(1*0.082L*298)/(1) \\ V=24.436L \end{gathered}`

Hence the one mole of any gas occupies a volume of 24.436L