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6) y < 6x + 1 y-axti a linear ineg points with -values? W 3 2 1 2

6) y < 6x + 1 y-axti a linear ineg points with -values? W 3 2 1 2-example-1

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6) y < 6x + 1

The first step is to make the expression to be an equation. Thus, we have

y = 6x + 1

We would assume values for x, substitute them into the equation and solve for the corresponding y values. Thus, we have

If x = 0, y = 6 * 0 + 1 = 1

If x = 1, y = 6 * 1 + 1 = 7

If x = 2, y = 6 * 2 + 1 = 13

We would plot these values on the graph. the line on the graph would be a broken line because the inequality symbol is simply "less than"

The graph is shown below

The shaded portion was determined by testing a point. If we test the point, (0, 0), it measn that we would substitute x = 0 and y = 0 into the inequality. Thus, we have

0 < 6 * 0 + 1

0 < 1

This is true. Thus, we shaded the portion of the graph containing (0,0)

6) y < 6x + 1 y-axti a linear ineg points with -values? W 3 2 1 2-example-1
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