From the given table, we have the points:
(x, y1) ==> (-10, -23), (-9, -19), (-8, -15), (-7, -11), (-6, -11), (-6, -7), (-5, -3), (-4, 1)
Let's write an equation in slope-intercept form using the given points.
Apply the slope-intercept form of a linear equation:
y = mx + b
Where m is the slope and b is the y-intercept.
To find the slope, m, apply the formula:

• Take any two points:
(x1, y1) ==> (-10, -23)
(x2, y2) ==> (-7, -11)
• Input the coordinates of the points in the formula for m:

The slope of the line, m, is 4.
Now, we have:
y = 4x + b
Plug in the coordinates of any point for x and y to solve for the y-intercept, b.
Take the last point:
(x, y) ==> (-4, 1)
We have:
1 = 4(-4) + b
1 = -16 + b
Add 16 to both sides:
1 + 16 = -16 + 16 + b
17 = b
b = 17
The y-intercept, b, is 17.
Therefore, the equation of the line in slope-intercept form is:
y = 4x + 17
ANSWER:
