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A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much forcedid the friend apply?

A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much forcedid the friend-example-1
User Misho
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1 Answer

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We are asked to determine the force acting upon a person given the mass and acceleration. To do that we will use Newton's second law, that is:


F=ma

Where "m" is the mass and "a" is the acceleration. Replacing the given values:


F=(50\operatorname{kg})(5(m)/(s^2))

Now we solve the product. We need to have into account that the product of the units is defined as N (newtons):


F=250N

Therefore, the force is 250 Newtons.

User AngryUbuntuNerd
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