Question

If U is between T and V with TU=5y-3, UV=33, and TV=10y find the measure of TV.

Answer 1

Using the diagram, we have the next equation

`\begin{gathered} 5y-3+33=10y \\ 10y-5y=30 \\ 5y=30 \\ y=6 \end{gathered}`

Then, TV = 10y=10(6)=60