6.6k views
0 votes
I will send u the picturea) 15, b) 18, c) 21, d) 225

I will send u the picturea) 15, b) 18, c) 21, d) 225-example-1
User Aamadmi
by
7.5k points

1 Answer

6 votes

length of AC = 15 (option A)

Step-by-step explanation:

We use the cordinates of A and C to find the distance of AC.

A = (-6, -5)

C = (6, 4)

The length of AC = distance of AC

Distance formula:


dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}
\begin{gathered} x_1=-6,y_1=-5,x_2=6,y_2\text{ = }4 \\ \text{distance AC = }\sqrt[]{(4-(-5))^2+(6-(-6))^2} \\ =\text{ }\sqrt[]{(4+5)^2+(6+6)^2} \end{gathered}
\begin{gathered} =\text{ }\sqrt[]{(4+5)^2+(6+6)^2}\text{ = }\sqrt[]{9^2+12^2} \\ \text{Distance AC = }\sqrt[]{81+144}\text{ = }\sqrt[]{225} \\ \text{Distance AC = 1}5 \\ \text{length of AC = }15\text{ (option A)} \end{gathered}

User Mark Wright
by
7.8k points