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y = (4)/(5)x - 1.5x=2 to x=6
y = (4)/(5)x + 3from x=0 to x=3

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10) You have the following equations of two lines, with definite intervals:

y = (4/5)x - 1.5 from x = 2 to x = 6

y = (4/5)x + 3 from x = 0 to x = 3

In order to grah the given lines, you first calculate the values of the functions for the limits of the intervals, just as follow:

from x = 2 to x = 6

y = (4/5)(2) - 1.5 = 0.1

y = (4/5)(6) - 1.5 = 3.3

from x = 0 to x = 3

y = (4/5)(0) + 3 = 3

y = (4/5)(3) + 3 = 5.4

Next, you graph the two lines by taking into account the limits, and you connect the endpoints of the segment, just as follow:

where the blue lines are the the given functions, and the orange lines are the connection between the endpoints of the functions.

y = (4)/(5)x - 1.5x=2 to x=6 y = (4)/(5)x + 3from x=0 to x=3-example-1
User David Seek
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