We have to transform each sentence into an algebraic expression.
"The difference between two numbers is 5" can be expressed as

"The sum of three times the larger number and twice the smaller number is 30" can be expressed as

Where x is the larger number, and y is the smaller number.
We form a system of equations with these two

We can multiply the first equation by 2 and sum them to find the first variable

Then, we divide the equation by 5

The larger number is 8.
Now, we find the smaller numbers using the first equation

The smaller number is 3.
Therefore, the right answer is C.