Question

Find the equation of a line that passes through (-2, 8) with a slope of 4.a. y=4x-16b. y=4x+16c. y=4x-24d. y=4x+24

Answer 1

The Solution.

Step 1:

We shall state the formula for equation of a line.

`\begin{gathered} y-y_1=m(x-x_1) \\ \text{Where m=slope=4} \\ (x_1,y_1)=(-2,8) \end{gathered}`

Step 2:

We shall substitute the above values into the formula.

`\begin{gathered} y-8=4(x--2) \\ y-8=4(x+2) \\ \text{Clearing the brackets, we get} \\ y-8=4x+8 \\ \text{Collecting the like terms},\text{ we get} \\ y=4x+8+8 \\ y=4x+16 \end{gathered}`

Step 3:

Presentation of the Answer.

The correct answer is y = 4x + 16 (option B)