irrational
Step-by-step explanation
![2√(7)-3√(7)](https://img.qammunity.org/2023/formulas/mathematics/college/b2aljnugdutu2uf8ko099whpq8oll532zz.png)
Step 1
simplify
![\begin{gathered} 2√(7)-3√(7) \\ 2√(7)-3√(7)=\left(2-3\right)√(7) \\ 2√(7)-3√(7)=(-)√(7) \\ 2√(7)-3√(7)=-√(7) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fvwbci009rn3yw7o7kfolq6bhwthytrm3u.png)
Step 2
A rational expression is the ratio of two polynomials. If f is a rational expression then f can be written in the form a/b where a and b are polynomials
![\begin{gathered} 2√(7)-3√(7)=-√(7) \\ -√(7)=-2.64575131106 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/93zhpewptjeblxd9hwmjm44kmkvsypxlyq.png)
It is an irrational number because evaluating √7 gives a non recurring, non terminating decimal number
it is impossible to find a value for –√7 which can be represented as a/b where a & b are integers.
so, the answer is
irrational
I hope this helps you